(2x+3)(x^2+3x-4)=0

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Solution for (2x+3)(x^2+3x-4)=0 equation: 


Simplifying
(2x + 3)(x2 + 3x + -4) = 0

Reorder the terms:
(3 + 2x)(x2 + 3x + -4) = 0

Reorder the terms:
(3 + 2x)(-4 + 3x + x2) = 0

Multiply (3 + 2x) * (-4 + 3x + x2)
(3(-4 + 3x + x2) + 2x * (-4 + 3x + x2)) = 0
((-4 * 3 + 3x * 3 + x2 * 3) + 2x * (-4 + 3x + x2)) = 0
((-12 + 9x + 3x2) + 2x * (-4 + 3x + x2)) = 0
(-12 + 9x + 3x2 + (-4 * 2x + 3x * 2x + x2 * 2x)) = 0
(-12 + 9x + 3x2 + (-8x + 6x2 + 2x3)) = 0

Reorder the terms:
(-12 + 9x + -8x + 3x2 + 6x2 + 2x3) = 0

Combine like terms: 9x + -8x = 1x
(-12 + 1x + 3x2 + 6x2 + 2x3) = 0

Combine like terms: 3x2 + 6x2 = 9x2
(-12 + 1x + 9x2 + 2x3) = 0

Solving
-12 + 1x + 9x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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